posted by anon .
Write equivalent equations in the form of inverse functions for
(can you show how you would solve)
x= y+ cos è
cos è = x-y
theta = cos^-1(x-y)
cos(y) = x^2
y = Cos^-1(x^2)
They are both correct!
in a) is è a variable or a constant.
If it is a variable then we don't find an "inverse"
(the inverse is found by interchanging the x and y variables in a 2 variable relation)
original : cosy = x^2
inverse: cosx = y^2
solving this for y:
y = ±√cosx,
solving this for x:
x = cos^-1 (y^2) , where -1 < y < 1
Reiny, I interpret "inverse" being inverse trigonometric function, since he is doing a trigonometry course. However, I stand to be corrected!
You are right.
Funny how one's mind can get stuck along one track, and other possibilities get blocked.