A rectangular piece of gold is 2.6 cm long and 3.9 cm wide.The piece displays a resistance of 1.47 ìÙ when a current flows along the depth-direction.
In cm, how deep is the piece?
if a clinician changes the transmit power from 100 m watts to 1 m watt by how much has the transmit power changed
To determine the depth of the gold piece, we need to calculate its cross-sectional area. The resistance of a conductor is given by the formula:
Resistance = (Resistivity * Length) / Area
Here, the resistance is given as 1.47 ìÙ, and the length and width of the gold piece are given as 2.6 cm and 3.9 cm, respectively.
First, let's convert the resistance to ohms:
1.47 ìÙ = 1.47 * 10^(-6) Ù = 1.47 * 10^(-6) Ω
Since we know the length (L) as 2.6 cm and the width (W) as 3.9 cm, we need to find the area (A) of the cross-section:
Area (A) = L * W
Now we can rearrange the resistance formula to solve for the area:
Area (A) = (Resistivity * Length) / Resistance
However, we don't know the resistivity of gold. So, in order to find the resistivity of gold, we need one more measurement or value related to the gold piece, such as its mass or volume. With that information, we can calculate the resistivity and then determine the depth of the piece.