Calculus Please someone help

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1. Find the slope m and an equation of the tangent line to the graph of the function f a the point (2, 38)

2. Find an equation of the line that passes through the point (9,7) and is perpendicular to the line 5x+3y-4=0

  • Calculus - question incomplete -

    1. "the function" is not specified.
    2.
    The equation perpendicular to the line
    L: 5x+3y-4=0
    is
    L1 : 3x-5y+k=0
    where k is a constant to be determined.

    The equation of L1 is obtained by interchanging the coefficients of x and y, and changing the sign of x or y.

    The constant k can be determined by the fact that L1 passes through (9,7).
    3(9)-5(7)+k=0
    k=35-27=8
    So
    L1: 3x-5y+8=0

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