# precalculus

posted by josh

A bacteria culture initially contains 1500 bacteria and doubles every half hour.

a) Find an expression for the number of bacteria after t hours.
Q(t)=

b) The number of bacteria after 20 minutes is (the answer must be an integer)

c) The number of bacteria after 9 hours is

1. agrin04

(a) 1500*2^(t/0.5) = 1500*2^(2t)
(b) 1500*2^(2*20/60) = ?
(c) 1500*2^(2*9) = ?

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