# calculus

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For each function, find a. f''(x), and b. f''(3).

f(x)= 1
---
6x^2

• calculus -

f(x) = 1/(6x^2) = (1/6)x^(-2)
f'(x) = (-1/3)x^(-3)
f''(x) = x^(-4) = 1/x^4

As to answer question b, just change x with 3 and calculate the result

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