Physics

posted by .

Please Help!
An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100 degrees Celsius. After equilibrium is reached, the object is removed from the hot water and placed in 200 grams of water at 0 degrees Celsius. What is the final temperature of the object? Explain.

Thanks for the help!

  • Physics -

    You will have t do this problem in two steps.

    In step 1, determine the equilibrium temperature when the object is placed in the 100 C water. The heat lost by the water will equal the heat gained by the object. Write that equation and solve for the final temperature of that step, T1.

    (100 cal/C)*(T1-20)
    = (40 Cal/C)*(100 - T1)
    Solve for T1

    (100-T1)/T1-20) = 2.5
    100 - T1 = 2.5 T1 -50
    3.5 T1 = 150
    T1 = 42.8 C

    Once you have T1, write an analogous equation for the process of reaching thermal equilibrium in the second step. Then solve for the final equilbrium temperature, T2.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    Two solid objects, A and B, are placed in boiling water and allowed to come to temperature there. Each is then lifted out and placed in separate beakers containing 1000 g water at 10.0 degrees Celsius. Object A increases the water …
  2. AP Chemistry

    Two solid objects, A and B, are placed in boiling water and allowed to come to temperature there. Each is then lifted out and placed in separate beakers containing 1000 g water at 10.0 degrees Celsius. Object A increases the water …
  3. Physics

    Please Help! An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100 degrees Celsius. After equilibrium is reached, the object is removed from the hot water and placed in 200 grams …
  4. Physics

    Please Help! An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100 degrees Celsius. After equilibrium is reached, the object is removed from the hot water and placed in 200 grams …
  5. Physics

    Please Help! An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100 degrees Celsius. After equilibrium is reached, the object is removed from the hot water and placed in 200 grams …
  6. Physics

    Please Help! An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100 degrees Celsius. After equilibrium is reached, the object is removed from the hot water and placed in 200 grams …
  7. Physics 20

    1. How much heat energy is required to change 500 grams of water at 100 degrees Celsius to steam at 100 degrees Celsius?
  8. Physics

    Please Help! I am having difficulties grasping these concepts. Explain please! 1. How much heat energy is required to change 500 grams of water at 100 degrees Celsius to steam at 100 degrees Celsius?
  9. physica

    help A thermally insulated vessel containing 100 grams of ice at 0 degrees Celsius . Water at 55 degrees celsius is poured and after some time , the system reaches the equilibrium at a temperature of 10 degrees Celsius. That amount …
  10. Physical Science

    A hot metal spoon with a mass of 77.0 grams and a temperature of 95.0 degrees celsius is placed into a cup containing 100 grams of water at 20 degrees celsius. When the spoon and water reach equilibrium, they both have a temperature …

More Similar Questions