What volume at nitrogen would be required to react with 0.100g of hydrogen to produce ammomia?
I answered this below (technically, I didn't answer it but I gave you the information to answer it yourself.)
To determine the volume of nitrogen required to react with 0.100g of hydrogen, we need to use the balanced chemical equation for the reaction between hydrogen and nitrogen to produce ammonia.
The balanced chemical equation for the reaction is:
N₂ + 3H₂ → 2NH₃
From the balanced equation, we can see that 3 moles of hydrogen react with 1 mole of nitrogen to produce 2 moles of ammonia.
First, we need to calculate the number of moles of hydrogen present in 0.100g of hydrogen. We can use the molar mass of hydrogen to convert grams to moles.
The molar mass of hydrogen (H₂) is approximately 2.02 g/mol.
Number of moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen
Number of moles of hydrogen = 0.100g / 2.02 g/mol
Next, we can use the stoichiometry of the balanced equation to determine moles of nitrogen required. According to the balanced equation, 3 moles of hydrogen react with 1 mole of nitrogen.
Thus, moles of nitrogen required = Number of moles of hydrogen / (3 moles of hydrogen / 1 mole of nitrogen)
Finally, we need to convert moles of nitrogen to volume using the ideal gas law. At room temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.
Volume of nitrogen required = Moles of nitrogen required * 22.4 liters/mol
By following these calculations, we can determine the volume of nitrogen required to react with 0.100g of hydrogen and produce ammonia.