chemistry

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A 6.0 L flask contains a mixture of methane, argon and helium at 45 degrees C and 1.75 am. If the mole fractions of helium and argon are 0.25 and 0.35, respectively, how many molecules of methane are present?

  • chemistry -

    total mole fraction = 1.00 (always)
    XHe + XAr + XCH4 = 1.00
    Solve for XCH4.
    Then PCH4 = XCH4*Ptotal
    Use PV = nRT to solve for n
    Then remember there are 6.022E23 molecules in 1 mole.

  • chemistry -

    9.6*10^22

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