physics
posted by polo Q .
The force exerted by the wind on the sails of a sailboat is 500 N north. The water exerts a force of 150 N east. If the boat (including its crew) has a mass of 290 kg, what are the magnitude and direction of its acceleration?

Magnitude = pythagorean theorem (net force)
F^2=(500^2)+(150^2)=272500
F=square root(272500)
F=522 N *answer*
Acceleration:
a (m/s^2)= F/m= (522N/290Kg)
a=1.8 m/s^2 *answer*