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A stone is thrown vertically upward with a speed of 11.0 m/s from the edge of a cliff 80.0 m high. How much later does it reach the bottom of the cliff?

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    v=u+at
    0=11.0m/s+(-9.81)t
    11.0/9.81=t
    t=1.121304791
    total time
    t=2t
    t=2*1.121304791
    t=2.242609582
    t=2.24s

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