# Math - Calculus

posted by .

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2].

## Similar Questions

1. ### calculus

Use the Intermediate Value Theorem to show that there is a root in the equation x^(1/3)=1-x in the interval (0,1).
2. ### AP Calculus

Show that the equation x^3 - 15x + c = o has exactly one real root. All I know is that it has something to do with the Mean Value Theorem/Rolle's Theorem.
3. ### Math - Calculus

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2]. Perhaps Rolle's Theorem, Mean Value Theorem, or Intermediate Value Theorem hold clues?
4. ### Math - Calculus

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2]. Perhaps Rolle's Theorem, Mean Value Theorem, or Intermediate Value Theorem hold clues?
5. ### calc

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2].
6. ### Math

Show that the equation x^3-15x+c=0 has at most one root in the interval [-2,2].
7. ### Calculus

Let f(x)=3x^5+5x^3+15x+15. Use Rolle's Theorem to show that f(x) has exactly one root.
8. ### Math

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x^4+x-3=0, interval (1,2). According the to theorem, I found that a is 1, b is 2 and N is 0. f(1)= 2 and f(2) = 17. Is …
9. ### Calculus

Use the intermediate value therom to show that there is a root of the given equation in the specified interval. x^5-7=2(25-x); (2,3) Please explain for understanding and show work, Thank you in advance :)
10. ### math

show that the equation x^3-15x+c=0 has at most one root on the interval [-2,2.

More Similar Questions