Algebra 1

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Question:
The height in feet above the ground of an arrow t seconds after it is shot can be modeled by y = -16t(squared) + 63t + 4. Can the arrow pass over a tree that is 68 feet tall? Explain.

Completely lost, could anyone help me out?

  • Algebra 1 -

    y = height = -16t^2 + 63t + 4
    The vertex of this parabola is called the maximum point.

    Vertex = -b/2a
    Vertex = -63/(2(-16))
    Vertex = t value = 1.96875

    So, the maximum value for t seconds is 1.96875

    y = height = -16t^2 + 63t + 4
    t = 1.96875
    y = -16(1.96875)^2 + 63(1.96875) + 4
    y = -16(3.875977) + 124.0313 + 4
    y = 66.0157

    So, the maximum height = 66.0157 feet

    Use could also use derivatives to find the maximum value for t.

  • Algebra 1 -

    Thank you so much, this really helped! :)

  • Algebra 1 -

    You're welcome :)

  • Algebra 1 -

    dont do it

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