math probability
posted by Sam
Four balls are selected at random without replacement from an urn containing three white balls and five blue balls. Find the probability that two or three of the balls are white.

Reiny
prob (two are white) = C(4,2)((3/8)^2(5/8)^2
Prob(three are white = C(4,3)(3/8)^3(5/8)
add them up.
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