What is the area of this triangle 22 by 16 by 28 inches
area= sqrt (s(s-a)(s-b)(s-c))
where s is the half perimeter (1/2 perimeter) a, b, c are the three sides.
area = √(s(s-a)(s-b)s-c)) where a,b and c are the sides
and s = (1/2)perimiter.
s = (1/2)(22+16+28) = 33
s-a = 33-22 = 11
s-b = 33 - 16 = 17
s-c = 33 - 28 = 5
Area = √(33x11x17x5) = √30855
= 11√255
To find the area of a triangle, you can use the formula: area = (base × height) / 2.
In this case, the triangle has a base of 22 inches and a height of 16 inches. Plugging these values into the formula, we get:
area = (22 × 16) / 2
= 352 / 2
= 176 square inches
Therefore, the area of the triangle is 176 square inches.