algebra

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Graph the following equations; calculate the slope, x-intercept, and y-intercept, and label the intercepts on the graph.


Find the area of a rectangle if three of its corners are (-0.1,-3.4), (-7.9,-3.4), and (-0.1,6.8).

one I draw the graph how do I figure out the area of the rectangle?

  • algebra -

    Find the area of a rectangle if three of its corners are (-0.1,-3.4), (-7.9,-3.4), and (-0.1,6.8).

    You are given 3 points of the rectangle.
    You need to find the 4th point.

    Rectangle ABCD, labeled clockwise from the bottom horizontal segment.

    A(-0.1, -3.4)
    B(-7.9, -3.4)
    C(-7.9, 6.8)
    D(-0.1, 6.8)

    Point C was the missing point.
    It has the same x coordinate as Point B and the same y coordinate as D.

    A = LW
    AB = CD = the horizontal segments, the length
    BC = DA = the vertical segments, the width

    Use the distance formula to find the segment lengths

    Distance between AB
    A(-0.1, -3.4)
    B(-7.9, -3.4)
    D(A,B)=sqrt[(xA - xB)^2 + (yA - yB)^2]
    D = sqrt[(-0.1+7.9)^2 + (-3.4+3.4)^2]
    D = 7.8

    Distance between BC
    B(-7.9, -3.4)
    C(-7.9, 6.8)
    D(A,B)=sqrt[(xA - xB)^2 + (yA - yB)^2]
    D = sqrt[(-7.9+7.9)^2 + (-3.4-6.8)^2]
    D = 10.2

    A = LW
    A = (7.8)(10.2)
    A = ?

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