posted by leslie .
Light enters a plate of borosilicate crown glass
at an angle of 40.2 degrees with respect to the nor-
mal to the air-glass surface. If the index of
refraction of the glass is 1.52, find the angle
made by the refracted beam with the normal.
Answer in units of .
Snell's law says that
sin 40.2 = 1.52 sin(theta)
theta is the angle of refraction.
Solve for it.
sin(theta) = 0.4246
theta = 25.1 degrees