posted by Logan .
you have75.0ml of 2.5 M Solution of Na2CrO4(aq). You also have 125ml of a 1.74M solution of AgNO3(aq)Calculate the concentration of NO3 when the two solutions are added together
Nitrate never enters into the reaction.
Na2CrO4 + 2AgNO3 ==> Ag2CrO4 + 2NaNO3
(AgNO3) = 1.74M x 125 mL = 217.5 mmoles.
(NO3^-) at the end is 217.5 mmoles/total mL volume. That is 125 mL AgNO3 + 75 mL from the Na2CrO4. So nitrate = mols/L = or 217.5 mmoles/200 mL ??.