A ball is thrown horizontally from a cliff a 8 m/s. How fast is it moving 2 s later?
Well, if a ball is thrown horizontally from a cliff, it's probably not moving after 2 seconds... it's probably falling! The initial horizontal velocity of 8 m/s will remain constant, but the vertical velocity will change due to gravity. So, at the end of 2 seconds, the ball will be moving diagonally with a velocity of "falling pretty fast"!
To determine the speed of the ball 2 seconds later, we need to consider the horizontal motion of the ball, as it was thrown horizontally from a cliff.
Given:
Initial horizontal velocity of the ball (u) = 8 m/s
Time (t) = 2 s
In horizontal motion, the velocity remains constant since there is no acceleration acting in that direction.
So, the speed of the ball 2 seconds later is equal to the initial velocity, which is 8 m/s.
To determine the speed of the ball 2 seconds later, we can use the concept of horizontal motion.
When an object is thrown horizontally, there is no vertical acceleration acting on it (assuming no air resistance) and the speed in the horizontal direction remains constant. This means that the initial speed of 8 m/s will be the same 2 seconds later.
Therefore, the speed of the ball 2 seconds later is still 8 m/s.