# algebra

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Graph the following equation: clculte the slope, x-intercept, and y-intercept, and label the the intercelts on the graph.

problem: Find an equationin slope-intercept form passing through the points (2,5) and ( 7,-3).

(2+5)/(7+ -3) = 7/4
so y = (7/4)x +b
using (-2,5)
5= (7/4)(-2) +b
20= -3.5 +4b
b=?
I just can't see to figure it out

• algebra -

Equation passing through the points (2,5) and ( 7,-3)

Slope m = (-3 - 5)/(7 - 2)
m = -8/5

y = mx + b
y = -8/5 x + b

Using point, (2, 5) to find b
y = -8/5 x + b
5 = -8/5(2) + b
5 = -16/5 + b
b = 5 + 16/5
b = 25/5 + 16/5
b = 41/5

y = -8/5 x + 41/5
In the form, y = mx + b
b = y-intercept
y-intercept = 41/5

An x-intercept is a point on the graph where y is zero.

y = -8/5 x + 41/5
0 = -8/5 x + 41/5
-8/5 x = -41/5
x = -41/5 * -5/8
x = 41/8

x-intercept = 41/8

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