A 60.0-mL 0.508 M glucose (C6H12O6) solution is mixed with 115.0 mL of 2.43 M glucose solution. What is the concentration of the final solution? Assume the volumes are additive.
To find the concentration of the final solution, we can use the concept of dilution.
Dilution is the process of reducing the concentration of a solute in a solution, typically by adding more solvent. In this case, we are mixing two solutions of glucose, so we need to calculate the final concentration after the two solutions are combined.
First, let's calculate the moles of glucose in each solution:
Moles of glucose in solution 1 = Volume of solution 1 (in L) × Concentration of solution 1 (in mol/L)
Moles of glucose in solution 1 = 60.0 mL × (1 L / 1000 mL) × 0.508 mol/L
Moles of glucose in solution 1 = 0.03048 mol
Moles of glucose in solution 2 = Volume of solution 2 (in L) × Concentration of solution 2 (in mol/L)
Moles of glucose in solution 2 = 115.0 mL × (1 L / 1000 mL) × 2.43 mol/L
Moles of glucose in solution 2 = 0.27945 mol
Next, we add the moles of glucose from both solutions to find the total moles of glucose:
Total moles of glucose = Moles of glucose in solution 1 + Moles of glucose in solution 2
Total moles of glucose = 0.03048 mol + 0.27945 mol
Total moles of glucose = 0.30993 mol
Now, let's calculate the final volume of the solution:
Final volume of the solution = Volume of solution 1 + Volume of solution 2
Final volume of the solution = 60.0 mL + 115.0 mL
Final volume of the solution = 175.0 mL
Finally, we can use the formula for concentration:
Final concentration = Total moles of glucose / Final volume of the solution
Final concentration = 0.30993 mol / (175.0 mL × (1 L / 1000 mL))
Final concentration = 1.771 mol/L
Therefore, the concentration of the final solution is approximately 1.771 M.