Algebra II
posted by Renee .
how do you get the x inercept of a equation like 7/(4x^221x49)? I know you put it in y=mx+b but i don't know how to solve for x in this
Respond to this Question
Similar Questions

Algebra
5. Find the x and y intercepts of each linear equation. Be sure to write your answers as ordered pairs. y = 3x  6 6y = x + 2 The y intercepts is when x=0 So put in x=0 in each, and solve for y. The x intercepts is when y=0, put in … 
MATH
I NEED TO SOLVE FOR Y AND X im getting rele confused on this. ok here is the prob. x+y=5 x2y=4 equation 1 x+y=5 equation 2 x2y=4 Multiply equation 1 by 1. Add equation 1 to equation 2. The x term cancels. Solve for y. THEN, put … 
Algerbra
how do you solve 7(3x+4)=8(2x+5)+13 expand the parenthesis...I will do the left side.. 21x + 29= Now, subtract sixteen x from both sides, and subtract 28 from both sides. I will be happy to check your work. 7(3x+4)=8(2x+5)+13 21x + … 
algerbra
7(3x+4)=8(2x+5)+13 how would I start a equation like this would it be 21x+28=16x+40+13 ? 
Algebra
'L' has yintercept (0,3) and is parallel to the line with equation y=2/3x+1. (Instructions  write the equation of the line 'L' satisfying the given geometric conditions) We know that two lines that are parallel must have the same … 
algebra
factor the following equation: 6x^2  21x  9 i've tried to factor it and can only get answers for 6x^2  21x + 9! 
algebra
Problem Two: 5/9 + (2/9)x = 25/7 + (6/7)x – 2/3 Multiply figures inside parentheses 5/9 + (1 x 2/9x) = 25/7 + (1 x 6/7x) – 2/3 Collect like signs 5/9 + 2/9(6/7x) = 25/7 + (2/3) Multiply like signs 2 x 6 9 7 Reduce like numbers … 
Algebra 2
The problem is 3x^2  26 + 35 (We have to factor it!) So, I did the problem, but I'm not sure how to write the final answer. This is what my problem looks like so far: 3x^2  26 + 35 (3x^221x)(5x+35) 3x(x7)5(x+7) and this is where … 
Pre Algebra
I am having a problem with slopes and intercepts problems. Write each equation in slopeintercept form. Find slope and yinercept. 3x  y = 14 
Math
Ok so you're supposed to solve the system by method of substitution. And the problem is: 2/3x + y = 2 2x  3y = 6 So i put y= 2/3x into the second equation which looks like: 2x  3(2/3x + 2) = 6 and then 2x2x6=6 So like everything …