Two cars are moving in identical conditions, one car is moving 3 times how much farther will this fast car travel?
To determine how much farther the fast car will travel compared to the slow car, we need to consider the speed and time of both cars. Let's assume that the slow car travels a distance of "d" units, and the fast car travels 3 times the distance of the slow car.
The formula for calculating distance is:
Distance = Speed x Time
Let's assume that the speed of both cars is the same, denoted as "s" units. Now, we can calculate the time it takes for each car to travel their respective distances.
For the slow car:
Distance (d) = Speed (s) x Time (t)
Therefore, Time (t) = Distance (d) / Speed (s) ------------(1)
For the fast car:
Distance (3d) = Speed (s) x Time (T)
Therefore, Time (T) = Distance (3d) / Speed (s) -----(2)
Now, let's compare the time taken by both cars:
Time taken by the fast car (T) = (Distance of the fast car) / (Speed of the fast car)
= (3d) / (s)
Time taken by the slow car (t) = (Distance of the slow car) / (Speed of the slow car)
= (d) / (s)
Now, if we calculate the ratio of the time taken by the fast car to the time taken by the slow car, we get:
(T) / (t) = (3d) / (s) / (d) / (s)
= 3d / d
= 3
This means that the fast car will take three times less time to travel the same distance as the slow car.
Therefore, the fast car will travel three times farther than the slow car.