an object travelling at 10m/s accelerates at 4m/s2 for 8 seconds.what is the final velocity and how far does it travel during the 8 seconds
vf=vi+at
d=vi*t+1/2 a t^2
42m/s and 208m
To find the final velocity and the distance traveled during the 8 seconds, we can use the following formulas:
Final velocity (v) = Initial velocity (u) + (acceleration × time)
Distance (s) = (Initial velocity × time) + (0.5 × acceleration × time^2)
In this case, the initial velocity is not given, so we assume it to be 0 since no value is mentioned. Let's use these formulas to find the final velocity and distance traveled:
1. Final velocity:
v = u + (a × t)
= 0 + (4 × 8)
= 32 m/s
So, the final velocity is 32 m/s.
2. Distance traveled:
s = (u × t) + (0.5 × a × t^2)
= (0 × 8) + (0.5 × 4 × 8^2)
= (0.5 × 4 × 64)
= 128 m
Therefore, the object travels a distance of 128 meters during the 8 seconds.