A spring exerts a restoring force of 2.8 N to the right, in the positive x-direction. The spring constant is 7.3 N/m. Find the displacement of the end of the spring (with its sign). in meters??

To find the displacement of the end of the spring, we can use Hooke's Law, which states that the restoring force of a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be written as: F = -kx

Where:
F is the restoring force (in this case, 2.8 N)
k is the spring constant (in this case, 7.3 N/m)
x is the displacement of the spring

Rearranging the equation, we have:
x = -F/k

Substituting the given values:
x = -(2.8 N) / (7.3 N/m)

x ≈ -0.3835 m (rounded to four decimal places)

Therefore, the displacement of the end of the spring is approximately -0.3835 meters. The negative sign indicates that the displacement is in the opposite direction of the applied force.