A spring with spring constant 26 N/m is stretched 0.29 m in the positive x direction, referring to the figure. What is the spring’s restoring force (with its sign)? in newtons?

To calculate the spring's restoring force, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = -kx

Where F is the restoring force, k is the spring constant, and x is the displacement.

In this case, the spring constant is given as 26 N/m, and the displacement is 0.29 m.

Plugging in these values into the formula:

F = -26 N/m * 0.29 m

Calculating this expression:

F = -7.54 N

The negative sign indicates that the restoring force is in the opposite direction of the displacement, so the spring is trying to pull back in the negative x direction.

Therefore, the spring's restoring force is -7.54 N.