Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Calculus
Limits
limit as h approaches 0 :
((23.1^(6+h))-(23.1^6)) all that divided by (h)
1 answer
Figured it out!
You can
ask a new question
or
answer this question
.
Similar Questions
What is the limit as t approaches -8 of (t+10) divided by (t+8) to the power of 4?
A) -2 B) 0 C) 1 D) Undefined
Top answer:
To find the limit as t approaches -8 of (t+10)/(t+8)^4, we can substitute -8 into the expression and
Read more.
The table below gives selected values of a twice differentiable function f(x)
x|. -7. -6. -4. -2. f(x)|. 0. -1. -2. 0 f'(x)|. 3.
Top answer:
f(3(-2)-1)/(-2)^2 - 4 = f(-7)/4 - 4 = 0 - 4 = -4 Now, if you meant f(3x-1)/(x^2-4) then that would
Read more.
The limit as x approaches infinity. (1)/(5^x)
The limit as x approaches 1. (1-x^3)/(2-sqrt(x^2-3)) Show your work thanks in
Top answer:
what do you think? Both are straighforward, with the caveat the second has a complex number limit(it
Read more.
lim (1+x)^1/x. Give an exact answer.
x->0 This reads: The limits as x approaches zero is (1 plus x) to the 1 divided by x. The
Top answer:
To find the exact answer to the limit, lim (1+x)^(1/x) as x approaches 0, you can first take the
Read more.
Could someone please help me with these questions;I was having trouble with these four questions.
Evaluate each limit, if it
Top answer:
1.) Ah, the good old limit as u approaches 4 of (u^2 - 16) / (u^3 - 64). Well, let's see what we can
Read more.
What is the limit of this function as x approaches 0?
cos(x) - 1 / x From what I gather, the limit is equal to 0, since on the
Top answer:
There are several ways to get at this limit. Using L'Hopital's Rule, if f/g = 0/0, then the limit is
Read more.
use the rule that says
limit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 =
Top answer:
To show that the limit of [ln(x+h) - ln(x)]/h as h approaches 0 is equal to 1/x, where x > 0, we can
Read more.
use the rule that says
limit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 =
Top answer:
ln(x+h)-lnx = ln[1 + (h/x)= -> h/x for x ->0 Divide that by h and you get 1/x. The limit as x->0 is
Read more.
use the rule that says
limit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 =
Top answer:
To prove the limit of [ln(x+h) - ln(x)]/h as h approaches 0 is equal to 1/x, where x > 0, we can use
Read more.
Find the following limit if it exists, or explain why it does not exist:
lim as x approaches -infinity of square root of
Top answer:
lim x->-∞ √(9x^6-x^2)/(x^3+5) = ∞/∞ so we use derivatives a few times to get As x gets huge,
Read more.
Related Questions
What is the limit of g(x)=x as x approaches pi?
Would it just be pi??
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)
If the limit as x approaches 1 for (f(x) - 7)/(x-1)=8,
evaluate the limit as x approaches 1 for f(x)
Select EVERY graph that shows the end behavior described:
As x approaches −∞, f(x) approaches −∞. As x approaches ∞,
Hi,
I am trying to figure out what the limit as h approaches 0 of (1-2h)^(1/h) is. I am unfamiliar with the process I am supposed
Determine the behavior of limits
A. Limit as x approaches 1 of: (log x)/((x-1)^2) B. Limit as x approaches infinity of:
what is the end behavior of the function shown in the graph above? (1 point) responses as x approaches 0, y approaches 15. and
What is the end behavior of the function shown in the graph above?
(1 point) Responses As x approaches ∞, y approaches 0. and
Evaluate the limit:
Limit as x approaches 6 from the right: Sq.root of (x - 6). I know the limit is 0, but how do I show this?
1. Use the Taylor series to calculate the limit.
Problem: limit as x approaches 0 is equal to (1-cos(x))/(1+x-e^x). I did the