If the speed of light through material Z is
2.5×10^8 m/s, what is this material’s index of
refraction? The speed of light in a vacuum is
3 × 10^8 m/s.
(3x10^8)/x = 2.5 x 10^8
x= 1.2
Well, if the speed of light in a vacuum is 3 × 10^8 m/s and the speed of light through material Z is 2.5 × 10^8 m/s, then it seems like material Z is a bit of a slowpoke when it comes to letting light pass through.
To find the index of refraction, we can use the formula:
Index of refraction = speed of light in vacuum / speed of light in material
So in this case, let's plug in the numbers:
Index of refraction = (3 × 10^8 m/s) / (2.5 × 10^8 m/s)
Math, math, math...
Index of refraction ≈ 1.2
So the index of refraction for material Z is approximately 1.2. It's not exactly a speed demon, but hey, we all have our own pace, right?
To find the index of refraction of material Z, we can use the formula:
Index of refraction (n) = Speed of light in vacuum (c) / Speed of light in material (v)
Given:
Speed of light in vacuum (c) = 3 × 10^8 m/s
Speed of light in material Z (v) = 2.5 × 10^8 m/s
Substituting these values into the formula, we have:
Index of refraction (n) = (3 × 10^8 m/s) / (2.5 × 10^8 m/s)
Calculating this expression, we get:
Index of refraction (n) = 1.2
Therefore, the index of refraction of material Z is 1.2.
To find the index of refraction (n) of material Z, you can use the formula:
n = c/v,
where "c" is the speed of light in a vacuum (3 × 10^8 m/s) and "v" is the speed of light through material Z (2.5 × 10^8 m/s).
Substituting the given values into the formula, we have:
n = (3 × 10^8 m/s) / (2.5 × 10^8 m/s).
Now, let's simplify this expression:
n = 1.2.
So, the index of refraction of material Z is approximately 1.2.
n=c/v
where
n =the index of refraction
c =the speed of light in vacuum
v =the speed of light in a medium
find n
http://physics.info/refraction/