A 5.0 kg bullet hits a 2.0 kg block of wood at 400. m/sec and is imbeeded in it. What will be the velocity of wood and bullet after impact?
Try applying the Law of Conservation of Momentum. It isn't hard.
Initial momentum = Final momentum
The bullet and block have the same velocity the bullwet is embedded.
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To find the velocity of the wood and bullet after the impact, we can use the principle of conservation of momentum. According to this principle, the total momentum before the impact is equal to the total momentum after the impact.
The momentum of an object can be calculated by multiplying its mass by its velocity.
Let's assume that the velocity of the wood and bullet, after the impact, is represented by the variable "V". We can set up the equation as follows:
(mass of bullet × velocity of bullet before impact) + (mass of wood × velocity of wood before impact) = (mass of bullet + mass of wood) × velocity after the impact
Using this equation, we can substitute the given values:
(5.0 kg × 400 m/s) + (2.0 kg × 0 m/s) = (5.0 kg + 2.0 kg) × V
Now, solve the equation:
(2000 kg·m/s) = (7.0 kg) × V
V = 2000 kg·m/s / 7.0 kg
V ≈ 285.7 m/s
Therefore, the velocity of the wood and the bullet after the impact is approximately 285.7 m/s.