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A speeder passes a police car while traveling 130km/h. the police car imediently starts to accelerate at 10m/s^2 until the police car catches up to the speeder. how long does it take the police car to catch up?

  • physics -

    First, convert the speed to m/s

    Vcar = 130 km/h = 36.11 m/s

    Solve for t:

    36.11*t = (a/2) t^2 = 5 t^2

    where a is the acceleration rate of the poice car.

    Ignore the t=0 solution. Take the other one.

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