What mass of oxygen is contained in 10.5 micromoles of Cr(NO3)3 * 6H20?
To find the mass of oxygen contained in 10.5 micromoles of Cr(NO3)3 * 6H2O, we need to calculate the molar mass of Cr(NO3)3 * 6H2O and then determine the number of moles of oxygen present in the compound.
Step 1: Calculate the molar mass of Cr(NO3)3 * 6H2O.
To calculate the molar mass, we need to sum the atomic masses of all the constituent atoms in the compound.
Molar mass of Cr(NO3)3:
Cr: 1 atom x atomic mass of Cr = atomic mass of Cr
N: 3 atoms x atomic mass of N = atomic mass of N
O: 9 atoms x atomic mass of O = atomic mass of O
Total molar mass of Cr(NO3)3 = atomic mass of Cr + atomic mass of N + atomic mass of O
Molar mass of H2O:
H: 12 atoms x atomic mass of H = atomic mass of H
O: 6 atoms x atomic mass of O = atomic mass of O
Total molar mass of H2O = atomic mass of H + atomic mass of O
Add the molar mass of Cr(NO3)3 and 6H2O to get the total molar mass of Cr(NO3)3 * 6H2O.
Step 2: Calculate the number of moles of oxygen present in the compound.
Since there are 6 moles of water molecules in the compound, and each water molecule contains 1 mole of oxygen, we can multiply the number of moles of Cr(NO3)3 * 6H2O by 6 moles to get the number of moles of oxygen.
Finally, multiply the number of moles of oxygen by the molar mass of oxygen to find the mass of oxygen.
Note: Remember to convert micromoles to moles if necessary.
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