how many milliliters of 0.0850 m naoh are required to titrate 50.0 ml of a solution that contains 1.85 g of hcl per liter to the equivalence point?
To solve this problem, we need to use the concept of stoichiometry. Let's break down the steps to determine the answer:
1. Start by calculating the number of moles of HCl present in the solution.
Given:
- Concentration of HCl solution = 1.85 g/L
- Volume of HCl solution = 50.0 mL = 0.0500 L
We can calculate the number of moles of HCl using the formula:
moles = (mass) / (molar mass)
The molar mass of HCl is the sum of the molar masses of hydrogen (1 g/mol) and chlorine (35.5 g/mol). Thus, the molar mass of HCl is 36.5 g/mol.
moles of HCl = (1.85 g/L) / (36.5 g/mol) * (0.0500 L)
moles of HCl = 0.0025 mol
2. Next, we need to set up a balanced chemical equation between NaOH and HCl.
The balanced equation for the reaction is:
NaOH + HCl -> NaCl + H2O
From the equation, we can see that one mole of NaOH reacts with one mole of HCl.
3. Now, let's determine the number of moles of NaOH required to reach the equivalence point.
The stoichiometric ratio shows that 1 mole of NaOH reacts with 1 mole of HCl. Therefore, the number of moles of NaOH required will be the same as the number of moles of HCl.
moles of NaOH = 0.0025 mol
4. Finally, let's calculate the volume of 0.0850 M NaOH required to reach the equivalence point.
Given:
- Concentration of NaOH = 0.0850 M
The formula to calculate volume is:
volume (L) = (moles) / (concentration)
volume = (0.0025 mol) / (0.0850 mol/L)
volume = 0.0294 L
Since the question asks for the answer in milliliters, we need to convert liters to milliliters:
volume = 0.0294 L * (1000 mL/L)
volume = 29.4 mL
Therefore, 29.4 milliliters of 0.0850 M NaOH are required to titrate 50.0 mL of a solution containing 1.85 g of HCl per liter to the equivalence point.
You may be able to get away with no caps for sentences but lower case letters will NOT get it for formulas. There is no such thing as naoh or hcl. I assume you may have meant NaOH and HCl. In addition note that m and M mean two different things. Again, I ASSUME you meant M.
NaOH + HCl ==> NaCl + H2O
moles HCl = grams/molar mass
M HCl = moles/L soln.
mLNaOH x MNaOH ==> mLHCl x MHCl