How many ml of 1M HCl would you need to make 50.0 mL of 0.125M solution?
mLsoln1 x Msoln1 = mLsoln2 x Msoln2
5ml
To determine the number of milliliters (mL) of 1M HCl needed to make a 50.0 mL 0.125M solution, we can use the formula for dilution:
C₁V₁ = C₂V₂
Where:
C₁ = initial concentration of the solution (1M)
V₁ = initial volume of the solution (unknown)
C₂ = final concentration of the solution (0.125M)
V₂ = final volume of the solution (50.0 mL)
Rearranging the formula to solve for V₁, we have:
V₁ = (C₂ * V₂) / C₁
Plugging in the given values:
V₁ = (0.125M * 50.0 mL) / 1M
V₁ = (0.125 * 50.0) mL
Calculating the numerator:
0.125 * 50.0 = 6.25
Thus, V₁ = 6.25 mL.
Therefore, you would need 6.25 mL of 1M HCl to make 50.0 mL of a 0.125M solution.