Calculate the volkume of 0.750 M KNO3 that contains 17.0 grams of KNO3?
moles KNO3 = grams/molar mass
M = moles/L soln.
To calculate the volume of a solution, we need to use the formula:
volume = mass / concentration
First, let's convert the given mass of KNO3 from grams to moles. To do this, we need to know the molar mass of KNO3, which can be found by adding up the atomic masses of its components: potassium (K), nitrogen (N), and oxygen (O).
- The atomic mass of potassium (K) is 39.10 g/mol.
- The atomic mass of nitrogen (N) is 14.01 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
So, the molar mass of KNO3 is:
(39.10 g/mol) + (14.01 g/mol) + (3 × 16.00 g/mol) = 101.10 g/mol
Now, we can convert the mass of KNO3 from grams to moles:
17.0 g / 101.10 g/mol = 0.168 moles
Next, we need to calculate the volume of the solution using the given concentration of KNO3. The concentration is given as 0.750 M, which means there are 0.750 moles of KNO3 in 1 liter (1000 mL) of solution.
To find the volume in liters, we use the formula:
volume = moles / concentration
volume = 0.168 moles / 0.750 M = 0.224 L
Finally, we need to convert the volume from liters to milliliters (mL) since the solution volume is usually expressed in milliliters:
0.224 L × 1000 mL/L = 224 mL
Therefore, the volume of the 0.750 M KNO3 solution containing 17.0 grams of KNO3 is 224 mL.