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physics

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A 1-kg rocket is fired straight up from level ground. The engine is able to provide a constant 15N of thrust for exactly 5 seconds after which it shuts of completely. Find the maximum height that the rocket achieves.

  • physics -

    WEll, the impulse given is 15*5 Ns=75Ns

    Velocity at burnout= 75Ns/1= 75m/s

    What was its altditude at this point?

    Vf^2=Vi^2+2ad
    where a= (F/m -g)

    solve for d (height hi)

    Now, final height

    Vf^2=0=75^2-2g(hf-hi)

    solve for hf.

  • physics -

    thanks so much...i got 33.3m/s...would u say that's correct?

  • physics -

    sorry that was 188 that i got

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