A electrician charges $50 for the first half-hour of work and $30 each hour for additional time. Stoney Point High School budgeted $200 to repair the refrigeration system. What length of service call with the budget not be exceeded?
50(.5x) + 30x < 200
Solve for x.
Revised answer:
Subtract the cost of the first half hour from the total leaving you 150 for the remaining hours.
30x < 150
x < 5
However, now you need to add back in the extra half hour, so the length of the call cannot exceed 5.5 hours.
To determine the length of the service call that will not exceed the budget, we need to calculate how many additional hours the electrician can work within the allocated amount.
Let's start by subtracting the initial cost of $50 for the first half-hour from the budget of $200:
Remaining budget = Budget - Initial cost = $200 - $50 = $150
Now, let's determine how many hours the electrician can work with the remaining budget:
Additional hours = Remaining budget / Cost per hour = $150 / $30 = 5 hours
Since the electrician charges $30 for each additional hour, the maximum length of the service call that will not exceed the budget is 5 hours.