Physics
posted by Lynn .
A 100.0 W light bulb hangs from the ceiling. What is the visible light intensity on the floor, 2.1 m directly below the bulb, if 10% of its output is visible light?
So I am attempting to use: I= Power/area
however, I don't have a radius. I know 10% of 100 is 10 so that would be the intensity for that and that the refraction for air should be used but I am missing something...
HELP :)

The radius is R = 2.1 m. The light is distributed uniformly over a sphere of that radius, at that distance. So divide 10 W by 4*pi*R^2 and you will have the visible light irradiance.
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