1. Finde the area of the following tringles: (use Logarithms)

A) a=12.7, b=21.5, c=28.6.

i'm not of the answer i got.
i got 127.6
if you got something different can you show me how you did while using logarithms.

The fomula to use is

Area = sqrt[p(p-a)(p-b)(p-c)]
where p is the perimeter.

Whether you use logarithms or not to do the calculation is up to you.

Your answer is correct.

In my previous answer, "p" is HALF the perimeter, 31.4.

For additional steps, see
http://askville.amazon.com/Find-area-triangles-logarithms-a%3D12-b%3D21-c%3D28/AnswerViewer.do?requestId=1256937

To find the area of a triangle using logarithms, you can use Heron's formula. Heron's formula states that the area of a triangle with side lengths a, b, and c is given by:

Area = √(s(s-a)(s-b)(s-c))

where s is the semiperimeter of the triangle, calculated by:

s = (a + b + c) / 2

Let's calculate the area for the given triangle with side lengths a = 12.7, b = 21.5, and c = 28.6 using logarithms:

1. Calculate the semiperimeter:
s = (a + b + c) / 2 = (12.7 + 21.5 + 28.6) / 2 = 31.4

2. Calculate the expression inside the square root using logarithms:
Let L = log(s) + log(s-a) + log(s-b) + log(s-c)

First, calculate log(s):
log(s) = log(31.4)

Then, calculate log(s-a), log(s-b), and log(s-c):
log(s-a) = log(31.4 - 12.7)
log(s-b) = log(31.4 - 21.5)
log(s-c) = log(31.4 - 28.6)

3. Add the logarithms together to find L:
L = log(s) + log(s-a) + log(s-b) + log(s-c)

4. Calculate the area:
Area = 10^(L/2)

Once you compute L, calculate 10^(L/2) to find the area.

Now, let me calculate the area of the given triangle using the above steps:

s = (12.7 + 21.5 + 28.6) / 2 = 31.4

log(s) = log(31.4)
log(s-a) = log(31.4 - 12.7)
log(s-b) = log(31.4 - 21.5)
log(s-c) = log(31.4 - 28.6)

L = log(s) + log(s-a) + log(s-b) + log(s-c)

Finally, compute the area:
Area = 10^(L/2)

Please give me a moment to finish the calculations.