How many moles of argon gas are present in 70L of volume with a pressure of 180atm at 21c?
To calculate the number of moles of argon gas, you can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (in atm)
V = Volume (in liters)
n = Number of moles
R = Ideal gas constant (0.0821 L.atm/mol.K)
T = Temperature (in Kelvin)
First, we need to convert the given values to the appropriate units.
Pressure: Given as 180 atm
Volume: Given as 70 L
Temperature: Given as 21°C. To convert Celsius to Kelvin, add 273.15. So 21°C + 273.15 = 294.15 K.
Now we can substitute the values into the ideal gas law equation and solve for the number of moles (n):
(180 atm) * (70 L) = n * (0.0821 L.atm/mol.K) * (294.15 K)
(180 atm * 70 L) / (0.0821 L.atm/mol.K * 294.15 K) = n
After performing the calculation, we can determine the number of moles of argon gas in the given conditions.