posted by mNoellb .
As a woman walks, her entire weight is momentarily supported on the heel of one shoe. Calculate the pressure exerted on the floor by a high-heel shoe worn by a 50-kg woman if the heel has an area of 2.0cm^2. Express the pressure in newtons per square meter and atmospheres.
I am using the formula :
P= F/A => F=mg A= 3.14(r^2)
I have the answer in my book so I know I'm not getting the formula right and I don't know why. Can someone please help me.
Heel pressure = (weight)/(heel area)
The heel area must be expressed as 2*10^-4 m^2. The heel pressure is M*g/2*10^-4 m^2
The dimensions wil be Pascals if M is in kg and g is 9.8 m/s^2.
I get it now! lol Thank you!
(50 kg)(9.8 m/sec^2)
2.45 * 10^6 N-m or Pa