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solve by elimination

  • math -

    1st - 5(3rd) ---> 23y - 5z = -66
    2nd - 2(3rd) ---> 13y - 5z = -36

    subtract those ----> 10y = 30
    y = 3

    back in 13y-5z=-36
    39 - 5y = -36
    -5z = 75
    z = -15

    put y=3 and z=-15 into the original 3rd and you are done.

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