How many total moles of ions are released into water when 0.50 moles of calcium perchlorate are dissolved in a liter of water?
Ca(ClO4(2 ==> Ca^+2 + 2ClO4^-
0.50 mole Ca^+2 + 1.00 mole ClO4^- = 1.50 total moles.
To find out how many total moles of ions are released when calcium perchlorate is dissolved in water, we need to first determine the number of ions produced by this compound.
Calcium perchlorate (Ca(ClO4)2) dissociates into calcium ions (Ca2+) and perchlorate ions (ClO4-) when dissolved in water. Each formula unit of calcium perchlorate produces three ions: one calcium ion and two perchlorate ions.
So, for every formula unit of calcium perchlorate, we have 1 Ca2+ ion and 2 ClO4- ions.
Given that we have 0.50 moles of calcium perchlorate, we can multiply this by the number of ions produced per mole of calcium perchlorate to find the total moles of ions produced.
1 mole of calcium perchlorate produces 1 mole of Ca2+ ions and 2 moles of ClO4- ions.
Therefore, for 0.50 moles of calcium perchlorate:
- We have 0.50 moles of Ca2+ ions.
- We have 0.50 moles * 2 = 1.00 moles of ClO4- ions.
In total, when 0.50 moles of calcium perchlorate are dissolved in water, there are 0.50 moles of Ca2+ ions and 1.00 moles of ClO4- ions released.