Calculus 2nd Post please help
posted by Anonymous .
Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point.
(x  y  1)3 = x; (1, 1)

I will assume your equation is
(x  y  1)^3 = x
then 3(xy1)^2(1  dy/dx) = 1
at the given point...
3(1+11)^2(1dy/dx) = 1
3  3dy/dx = 1
dy/dx = 2/3
so now you have the slope m=2/3 and the point (1,1)
Use the method you learned in grade 9 to find the equation of that line.
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