posted by eric .
A projectile is fired in such a way that its horizontal range is equal to 8.5 times its maximum height. What is the angle of projection?
From h = V^2(sin2µ)/2g and d = V^2(sin^2µ)/g:
d = V^2(sin2µ)/32 = 8.5V^2(sin^2µ)/32 yielding µ = 25.2º.