Calculus please help
posted by Brian .
please help I can not understand this.
I need an implicit form answer for the general solution of differential equation dy/dx=2(e^xe^x)/y^2(e^x+e^x)^4 with (y>0). I have separated the y^2 to the left hand side to become 1/3y^3 but have no idea how to make the right hand side ready forintegration and what its integral is. Please help.

The integration is relatively straightforward because you will notice that the numerator is the derivative of the base of the denominator, thus a substitution using u=(e^x+e^(x)) will do the job.
For more details, see:
http://www.jiskha.com/display.cgi?id=1297960703
Respond to this Question
Similar Questions

calculus differential equation
Find in implicit form the general solution of differential equation dy/dx=2(e^xe^x)/y^2(e^x+e^x)^4 with (y>0). I know this requires a seperation of variables but I beyond that I am confused by how.Thanks. 
calculus differential equation
Find in implicit form the general solution of differential equation dy/dx=2(e^xe^x)/y^2(e^x+e^x)^4 with (y>0). I know this requires a seperation of variables but I beyond that I am confused by how.Thanks. 
Maths
Hi I am really sorry I now people have already attempted to help me with this one already, however I am still not able to understand, I really have not done a lot of these equations and am struggling. I have put a little more information … 
calculus
I posted this below, and no one answered. Please help with this very complicated question! Using 3(x3)(x^26x+23)^1/2, as the chain rule differentiation of f(x)=(x^26x+23). Please explain how I find the general solution to the differential … 
calculus
I posted this below, and no one answered. Please help with this very complicated question! Using 3(x3)(x^26x+23)^1/2, as the chain rule differentiation of f(x)=(x^26x+23). Please explain how I find the general solution to the differential … 
Calculus
Using 3(x3)(x^26x+23)^1/2, as the chain rule differentiation of f(x)=(x^26x+23). Please explain how I find the general solution to the differential equation dy/dx= 2/27(x3)SQUARE ROOT BEGINS (x^26x+23)/y SQUARE ROOT ENDS (y>0). … 
calculus
Please help. How do I separate the variables in the following differential equation dy/dx=(2/27)(x3)then square root (x^26x+23)/y where (y>0). Then give general solution in implicit form. Thank you so much if you can help. 
calculus
Please help. I have an implicit answer to a differential equation of 18y*sqrt(y)=(2(x^26x+23)^3/2)/3 plus arbitrary constant. What is the particular solution to this for which y=2 when x=1. And then express this particular solution … 
calculus
Sorry to post this again, but I am still unable to understand it and need help. Please help.1) Using 3(x3)(x^26x+23)^2 as the answer to differentiating f(x)=(x^26x+23)^3/2, which I have been able to do, I need to find the general … 
Calculus
Find the general solution for the differential equation. Leave your solution in implicit form. dx/dt=(2x)sqrt(1x)