Aspirin is synthesized in a reaction with a theoretical yield of 0.728 moles of aspirin.
What is the % yield of 1.26 g of aspirin is recovered
MW of aspirin is 180.15
thank you so much!
To calculate the percent yield, we need to compare the actual yield (1.26 g) with the theoretical yield (0.728 moles).
First, we need to convert the mass of aspirin recovered to moles using its molar mass (MW).
Given:
Mass of aspirin recovered = 1.26 g
Molar mass of aspirin (MW) = 180.15 g/mol
1. Calculate moles of aspirin recovered:
Moles = Mass / Molar mass
Moles = 1.26 g / 180.15 g/mol
Moles ≈ 0.007 mol (rounded to three decimal places)
Next, we can calculate the percent yield by comparing the actual yield to the theoretical yield expressed in moles.
Percent Yield = (Actual Yield / Theoretical Yield) * 100
Given:
Theoretical Yield = 0.728 moles (from the synthesis reaction)
Actual Yield = 0.007 moles (calculated above)
2. Calculate the percent yield:
Percent Yield = (0.007 mol / 0.728 mol) * 100
Percent Yield ≈ 0.96% (rounded to two decimal places)
Therefore, the percent yield of 1.26 g of aspirin recovered is approximately 0.96%.