Given: v with a power of 1 is 50 Ml and t with a power of 1 is 30 degrees c. what is the volume with a power of two when T with a power of 2 is 20 degrees C

To determine the volume with a power of 2 (v^2) when the temperature with a power of 2 (T^2) is 20 degrees Celsius, we can use the concept of direct proportionality between volume and temperature.

We are given that v^1 (volume with a power of 1) is 50 mL when t^1 (temperature with a power of 1) is 30 degrees Celsius.

First, let's set up a proportion by equating the ratios of v^1 to t^1 and v^2 to t^2:

(v^1 / t^1) = (v^2 / t^2)

Substituting the given values:
50mL / 30°C = v^2 / 20°C

Now, solve for v^2 by cross-multiplying:

(50mL)(20°C) = (30°C)(v^2)
1000mL°C = (30°C)(v^2)

Divide both sides of the equation by 30°C:

(1000mL°C) / (30°C) = v^2
33.33 mL = v^2

Therefore, the volume with a power of 2 (v^2) when temperature with a power of 2 (T^2) is 20 degrees Celsius is approximately 33.33 mL.