If you were given 0.021 milligrams of the compound,H3PO4, what would the mass of H in the sample be?
To find the mass of H in the given sample of H3PO4, we first need to know the molar mass of H3PO4.
1. Molar mass of H3PO4:
The molar mass of a compound is the sum of the molar masses of each individual atom in the compound. Let's find the molar mass of H3PO4.
The atomic masses of each element are:
- H (hydrogen) = 1.008 g/mol
- P (phosphorus) = 30.97 g/mol
- O (oxygen) = 16.00 g/mol
Now, calculate the molar mass of H3PO4:
Molar mass = (3 * H) + P + (4 * O)
Molar mass = (3 * 1.008 g/mol) + 30.97 g/mol + (4 * 16.00 g/mol) = 98.00 g/mol
So, the molar mass of H3PO4 is 98.00 g/mol.
2. Calculating the mass of H in the sample:
The given sample is 0.021 milligrams of H3PO4. To find the mass of H, we need to calculate the number of moles of H first.
Number of moles = mass / molar mass
Number of moles of H = 0.021 mg / 98.00 g/mol
Now, we convert milligrams to grams to match the units:
Number of moles of H = 0.021 mg / 1000 (to convert mg to g) / 98.00 g/mol = 2.14285714e-7 mol
Finally, to find the mass of H, we multiply the number of moles of H by the molar mass of H:
Mass of H = number of moles of H * molar mass of H
Mass of H = 2.14285714e-7 mol * 1.008 g/mol = 2.15827952e-7 grams
Therefore, the mass of H in the given sample of H3PO4 is approximately 2.15827952e-7 grams.