a car accelerates from 5 m/s to 21 m/s at a rate of 3m/s^2 how far does it travel while accelerating
Vf^2=Vi^2+2ad solve for d
A car starts from rest and accelerates for 7.1 s
with an acceleration of 3.5 m/s
2
.
How far does it travel?
Answer in units of m.
To find the distance traveled while accelerating, you can use the kinematic equation:
\(v^2 = u^2 + 2as\)
where:
- \(v\) is the final velocity (21 m/s),
- \(u\) is the initial velocity (5 m/s),
- \(a\) is the acceleration (3 m/s^2), and
- \(s\) is the distance traveled.
Rearranging the equation, we have:
\(s = (v^2 - u^2) / (2a)\)
Plugging in the values we have:
\(s = (21^2 - 5^2) / (2 * 3)\)
Calculating this expression will give you the distance traveled while accelerating.