Within the nucleus. What strength of electric field does a proton produce at the distance of another proton, about 4.00×10−15m away?
___N/c
To determine the electric field strength produced by a proton at a certain distance, we can use Coulomb's law. Coulomb's law states that the electric field strength (E) produced by a point charge is given by the equation:
E = k * (q / r^2)
Where:
E is the electric field strength,
k is Coulomb's constant (k ≈ 9 × 10^9 N m^2/C^2),
q is the charge of the point charge, and
r is the distance between the two charges.
In this case, we have two protons, and we want to find the electric field strength at a distance of 4.00 × 10^(-15) m away from one of the protons. Since both protons have the same positive charge, we can use the equation twice.
Step 1: Calculate the electric field strength produced by a single proton at a distance r = 4.00 × 10^(-15) m:
E1 = k * (q / r^2)
Step 2: Since both protons are identical, we can consider the electric field produced by one proton and multiply it by 2 to find the total electric field:
E_total = 2 * E1
Now let's substitute the values and calculate the electric field strength:
Step 1:
E1 = (9 × 10^9 N m^2/C^2) * (1.6 × 10^(-19) C) / (4.00 × 10^(-15) m)^2
Step 2:
E_total = 2 * E1
By performing the calculations, we can find the answer in N/C.