Write equation m=9/8 through (6,4) in slope intercept form
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y-y1/x-x1=m, (6,4) m=9/8. y-4/x-6=9/8, 8(y-4)=9(x-6), 8y-32=9x-54, 8y=9x-54+32 divide both by 8, 8y/8y=9x/8-22/8, Ans=y=9x/8-22/8
To write the equation of a line in slope-intercept form (y = mx + b), we need to determine the values of the slope (m) and the y-intercept (b).
Given that the line passes through point (6,4) and has a slope of 9/8, we can substitute these values into the equation and solve for the y-intercept (b).
Using the point-slope form of a linear equation, the equation can be written as:
y - y1 = m(x - x1)
Replacing (x1, y1) with (6, 4) and m with 9/8, we get:
y - 4 = (9/8)(x - 6)
Next, we simplify the equation:
y - 4 = (9/8)x - (9/8)(6)
y - 4 = (9/8)x - 54/8
y - 4 = (9/8)x - 27/4
Finally, rearranging the equation to slope-intercept form:
y = (9/8)x - 27/4 + 4
y = (9/8)x - 27/4 + 16/4
y = (9/8)x - 11/4
Therefore, the equation of the line passing through (6,4) with a slope of 9/8 in slope-intercept form is:
y = (9/8)x - 11/4